Shana wants to use all 62 feet of the fencing
Solution: Given that, Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. Therefore, Perimeter = 62 feet. Perimeter is given by …Sep 19, 2016 · Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the equation 2l + 2w = 62 to find the width of the run. Which statements are true of the solution? Check all that apply. The value of w is 10 feet. The value of w can be zero. Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the equation to find the width of the run. Which statements are true of the solution? a. The value of w is 10 feet. b. The value of w can be zero. c.
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16 Jan 2021 ... If u want to put on some quality mass, start ... feet almost all the time. I hiked and went ... Profile photo for Shana · Shana. Losing weight. · 1y.Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the equation 2 l plus 2 w equals 62 to find the width of the run. Which statements are true of the solution?All Questions +0 math -1 . 1154 . 1 +208 Micah has 56 feet of fencing to make a rectangular dog run in his yard. He wants the length to be 2.5 feet more than the width. Find the length, L, by solving the equation 2L + 2(L − 2.5) = 56. ...List the smallest width firsti ft to. FENCING Vanessa has 180 feet of fencing that she intends to use to build a rectangular play area for her dog. She wants the play area to enclose at least 1800 square feet. What are the possible widths of the play area?
Correct answers: 1 question: Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. she decides to make the length of the run 20 feet. she writes and solves the equation 2l + 2w = 62 to find the width of the run. which statements are true of the solution? check all that apply. the value of w is 10 feet. the value of w can be zero. the value of w cannot be ...Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the equation 2l+2w=62 to find the width of the run. Which statements are true of the solution? Check all that apply. The value of w is 10 feet The value of w can be zero The value ...62 = 2(3w + 4) 62 = 6w + 8 6w = 62 - 8 6w = 54 w = 54/6 w = 9 Therefore, the width of the garden is 9 feet. answered by Step-by-Step Bot; 6 months ago; 0; 0; To find the width of the garden, we need to set up an equation based on the information given. Let's assume the width of the garden is x feet. According to the given information, the ...Jun 20, 2016 · To find the width of a dog run for which Shana has 62 feet of fencing and plans a length of 20 feet, we use the equation 2l + 2w = 62, which reveals the width is 11 feet. Explanation: Finding the Width of a Rectangular Enclosure. Sep 4, 2023 · Shana correctly used the perimeter formula for a rectangle and found the width of the dog run to be 11 feet. Explanation: Shana is using the formula for the perimeter of a rectangle, which is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width. She knows the length (l) is 20 feet and the total perimeter is 62 feet.
You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Jonny wants to build a fenced garden, and was able to purchase 44 feet of fencing on sale. He intends to use all of the fencing to fence the garden. If he wants the length of the garden to be 8 feet more than the width what must the width ...Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the equation 2l + 2w = 62 to find the width of the run. Which statements are true of the solution? See Answer. Question: Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the equation 2 l plus 2 w equals 62 to find the width of the run. Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. ….
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Expert-verified. Recognize that the perimeter of a rectangle is the sum of all sides, or 2 ( l + w) where l is length and w is width. Andrea wants to build a rectangular play area for her dog using 36 feet of fencing. She wants the play area to be as large as possible. Determine the length and width, in feet of the play area Andrea should bulld.Miranda has 55 feet of fencing. She wants to use all the fencing to create a rectangular garden. The equation 2l+2w=55, where l is the length of the garden and w is the width, models the scenario. This equation can be used to find on dimension of the garden if the other dimension is known.
Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the …The problem Shana faces is determining the width of the dog run, given that she wants the length to be 20 feet and she has a total of 62 feet fencing to use. The equation she wrote to help solve this problem is 21 + 2W = 62. Here, W represents the width of the run in feet.
ezgo serial lookup Correct answers: 3 question: Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the equation to find the width of the run. Which statements are true of the solution? Check all that apply.Answer: Check boxes 3,4, and 5. Step-by-step explanation: It is given in the problem that the equation to find the width of the run is 2l+2w=62 and l=20 feet. You can plug in 20 for l in the previous equation by using Substitution. It should look like this: 2 (20)+2w=62. Next multiply 2 by 20 to get 40: 40+2w=62. truist jacksonville ncmadden playoff bracket Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the equation to find the width of the run. 00:21. A veterinarian is enclosing a rectangular outdoor running area against his building for the dogs he cares for. He … church of the blessed sacrament west lafayette Question: 10. Elissa wants to set up a rectangular dog run in her backyard. She has 32 feet of fencing to work with and wants to use it all. If the dog run is to be x feet long, express the area of the dog run as a function of x. There are 2 steps to solve this one.Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the equation 2 l plus 2 w equals 62 to find the width of the run. left antibiotics out of fridge overnightkidsongs let's learn about animalshutchpost com contest Question: Bob wants to fence in a rectangular garden in his yard. He has 76 feet of fencing to work with and it all. If the garden is to be x feet wide, express the area of the garden as a function of x A(x) = 40x^2 - x A(x) = 39x - x^2 A(x) = 37x - x^2 A(x) = 38x - x^2 A rectangle that is x feet wide is inscribed in a circle of radius 13 feet. how to disassemble a maytag washing machine Here’s the best way to solve it. Bob wants to fence in a rectangular garden in his yard. He has76 feet of fencing to work with and wants to use tan the garden is to be x feet wide, express the area of the garden as a function of x. A (x) = 38x-x^2 A (x) = 37x-x^2 A (x) = 39x - x^2 A (x) = 40x^2 - x. is emily compagno divorceliquid wisdom rogue lineageremote access epic Question 935989: A rancher wants to use 400 feet of fencing to enclose a rectangular area of 5100 square feet. What dimensions should the rectangle have? Found 3 solutions by josgarithmetic, lwsshak3, MathTherapy: Answer by …